Transfer regularity for the L to frequency in mL so that the systems getting thickness (grams mL -step one ) was consistent:

(ii) Maybe you’ve utilized the proper level of tall rates? occurrence (1.03 ) has actually step 3 high rates regularity (1) features step one extreme figure Whenever multiplying otherwise breaking up, what number of tall rates on result is an equivalent while the minimum quantity of tall numbers on the terms and conditions put, so we was rationalized in making use of step 1 high shape. The respond to (ten30) provides 4 high numbers! As the audience is only rationalized in making use of step one tall profile, we can allow the answer given that a thousand g, but the best solution would be to play with scientific notation and you may establish step one ? ten step three grams

(iii) Will be your respond to possible? Would a great “rough” calculation: thickness ≈ step one grams mL -step 1 1 mL regarding milk products have scores of from the step one g 1 L (a thousand mL) out-of dairy has actually quite a few from the one thousand ? step 1 = a thousand grams Because rough calculation is close to the brand new meticulously computed worth to own bulk we are fairly certain that our very own address is right.

Question 5. From the twenty-five°C and you may step 1 atm pressure, diamond has actually a density off step three.5 grams cm -step three . Determine the amount in the cm step 3 out-of 0.fifty g regarding diamond on twenty-five°C and you may 1 atm pressure.

3.5 grams cm -step three ? V (cm step 3 ) = V(cm step 3 ) ? 0.fifty grams ? V (cm step 3 ) 3.5 g cm -3 ? V (cm step three ) = 0.50 g

[ step 3.5 grams cm -step three ? V (cm step three )] ? step 3.5 g cm -3 = 0.50 g ? step 3.5 grams cm -3 V (cm 3 ) = 0.50 ? step three.5 (cm -3 ) = 0.14 cm 3

## Carry out an excellent “rough” calculation: occurrence ≈ 5 g cm -step three step one cm -step 3 regarding diamond provides scores of on 5 grams

(ii) Have you ever made use of the correct number of tall figures? density (step 3.5) possess 2 extreme numbers regularity (0.50) enjoys 2 significant numbers Whenever multiplying otherwise isolating, how many extreme data from the outcome is an equivalent due to the fact least amount of high rates regarding the terms and Italy disabled dating conditions utilized, so we is warranted in using 2 significant rates. Our answer (0.14) has actually dos extreme figures

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Matter six. Within twenty-five°C and you can 1 automatic teller machine stress, ethylene glycol keeps an occurrence of 1.eleven grams mL -step one . Calculate the quantity during the mL of 0.025 kilogram out of ethylene glycol in the twenty five°C and you may 1 automatic teller machine tension.

Move size when you look at the kg in order to size into the g in order to be consistent which have equipment out of occurrence (g mL -1 ):

V (mL) ? step one.eleven (g mL -step one ) = V (mL) ? twenty-five (g) ? V (mL) V (mL) ? step 1.eleven (g mL -step one ) = 25 (g)

## The question provides 0

[V (mL) ? step one.11 (g mL -1 ) ] ? step 1.eleven (g mL -1 ) = 25 (g) ? 1.eleven ( g mL -step 1 ) V (mL) = twenty-five ? step one.11 (mL -step one ) = 23 mL

(ii) Maybe you’ve made use of the proper number of significant data? bulk (0.025) possess dos high rates thickness (1.11) provides step 3 extreme numbers Whenever multiplying or isolating, what number of tall numbers regarding outcome is an identical as least quantity of high numbers regarding conditions made use of, therefore we was warranted in making use of dos extreme data. Our address (25) keeps 2 significant data